(2x)^2-10^2=(2x-10)(2x+10)

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Solution for (2x)^2-10^2=(2x-10)(2x+10) equation: 



(2x)^2-10^2=(2x-10)(2x+10)

We move all terms to the left:

(2x)^2-10^2-((2x-10)(2x+10))=0

We add all the numbers together, and all the variables

2x^2-((2x-10)(2x+10))-100=0

We use the square of the difference formula

2x^2+4x^2+100-100=0

We add all the numbers together, and all the variables

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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